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Solution for Solve dy/dx=2xy/(x^2y^2) Q A group of 150 tourists planned to visit East AfricaAmong them, 3 fall ill and did not come, of th A Consider the provided question, First draw the Venn diagram according to the given question, Let K r I'll start with the second one for you Take the natural logarithm of both sides ln(x^y * y^x) = ln(1) ln(x^y) ln(y^x) = 0 yln(x) xln(y) = 0 dy/dxln(x) y/x ln y x/y(dy/dx) = 0 dy/dx(lnx x/y) = lny y/x dy/dx= (lny y/x)/(lnx x/y) dy/dx= (ln y y/x)/(lnx x/y) Now for the second I would differentiate term by term Let t = x^y and u = y^x Then lnt = ln(x^y) and lnu#mathematic #preumath #iium #calculus안녕하세요, this is my video for teaching calculus i will make more problem solving videos soon Stay tuned😘🧸I wanna help Answered Rebecca Ferrer 2 26 Given Bartleby Example 9 if x^(y)+y^(x)=2 find (dy)/(dx)

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